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13124331222043 is a prime number
BaseRepresentation
bin1011111011111011111100…
…0110011011010000011011
31201110200012012122000110011
42332332333012123100123
53210012112243101133
643525122354102351
72523126106505326
oct276767706332033
951420165560404
1013124331222043
1141aaaa7908068
12157b6bbb7a9b7
137428082a4262
143353146a17bd
1517b5d99dc6cd
hexbefbf19b41b

13124331222043 has 2 divisors, whose sum is σ = 13124331222044. Its totient is φ = 13124331222042.

The previous prime is 13124331221951. The next prime is 13124331222047. The reversal of 13124331222043 is 34022213342131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13124331222043 - 217 = 13124331090971 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13124331221996 and 13124331222014.

It is not a weakly prime, because it can be changed into another prime (13124331222047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562165611021 + 6562165611022.

It is an arithmetic number, because the mean of its divisors is an integer number (6562165611022).

Almost surely, 213124331222043 is an apocalyptic number.

13124331222043 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124331222043 is an equidigital number, since it uses as much as digits as its factorization.

13124331222043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 13124331222043 its reverse (34022213342131), we get a palindrome (47146544564174).

The spelling of 13124331222043 in words is "thirteen trillion, one hundred twenty-four billion, three hundred thirty-one million, two hundred twenty-two thousand, forty-three".