Base | Representation |
---|---|
bin | 1011111011111011111100… |
… | …0110011011010000011011 |
3 | 1201110200012012122000110011 |
4 | 2332332333012123100123 |
5 | 3210012112243101133 |
6 | 43525122354102351 |
7 | 2523126106505326 |
oct | 276767706332033 |
9 | 51420165560404 |
10 | 13124331222043 |
11 | 41aaaa7908068 |
12 | 157b6bbb7a9b7 |
13 | 7428082a4262 |
14 | 3353146a17bd |
15 | 17b5d99dc6cd |
hex | befbf19b41b |
13124331222043 has 2 divisors, whose sum is σ = 13124331222044. Its totient is φ = 13124331222042.
The previous prime is 13124331221951. The next prime is 13124331222047. The reversal of 13124331222043 is 34022213342131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13124331222043 - 217 = 13124331090971 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13124331221996 and 13124331222014.
It is not a weakly prime, because it can be changed into another prime (13124331222047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562165611021 + 6562165611022.
It is an arithmetic number, because the mean of its divisors is an integer number (6562165611022).
Almost surely, 213124331222043 is an apocalyptic number.
13124331222043 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124331222043 is an equidigital number, since it uses as much as digits as its factorization.
13124331222043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 13124331222043 its reverse (34022213342131), we get a palindrome (47146544564174).
The spelling of 13124331222043 in words is "thirteen trillion, one hundred twenty-four billion, three hundred thirty-one million, two hundred twenty-two thousand, forty-three".
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