131243312324040 has 512 divisors, whose sum is σ = 458545350205440. Its totient is φ = 29431987200000.

The previous prime is 131243312324009. The next prime is 131243312324057. The reversal of 131243312324040 is 40423213342131.

It is a junction number, because it is equal to n+sod(n) for n = 131243312323992 and 131243312324010.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 9544267165 + ... + 9544280915.

It is an arithmetic number, because the mean of its divisors is an integer number (895596387120).

Almost surely, 2^{131243312324040} is an apocalyptic number.

131243312324040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131243312324040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (229272675102720).

131243312324040 is an abundant number, since it is smaller than the sum of its proper divisors (327302037881400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131243312324040 is a wasteful number, since it uses less digits than its factorization.

131243312324040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14653 (or 14649 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 131243312324040 its reverse (40423213342131), we get a palindrome (171666525666171).

The spelling of 131243312324040 in words is "one hundred thirty-one trillion, two hundred forty-three billion, three hundred twelve million, three hundred twenty-four thousand, forty".