13124333041 has 4 divisors (see below), whose sum is σ = 13174235712. Its totient is φ = 13074430372.

The previous prime is 13124333029. The next prime is 13124333051. The reversal of 13124333041 is 14033342131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13124333041 - 2⁷ = 13124332913 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13124332997 and 13124333015.

It is not an unprimeable number, because it can be changed into a prime (13124333051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24950941 + ... + 24951466.

It is an arithmetic number, because the mean of its divisors is an integer number (3293558928).

Almost surely, 2^13124333041 is an apocalyptic number.

It is an amenable number.

13124333041 is a deficient number, since it is larger than the sum of its proper divisors (49902671).

13124333041 is an equidigital number, since it uses as much as digits as its factorization.

13124333041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49902670.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13124333041 its reverse (14033342131), we get a palindrome (27157675172).

The spelling of 13124333041 in words is "thirteen billion, one hundred twenty-four million, three hundred thirty-three thousand, forty-one".