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13124335224137 is a prime number
BaseRepresentation
bin1011111011111011111101…
…0101101100010101001001
31201110200012111011100021212
42332332333111230111021
53210012114304133022
643525123015542505
72523126155514254
oct276767725542511
951420174140255
1013124335224137
1141aaaaa0a0985
12157b70138aa35
13742809075a67
1433531502409b
1517b5da02d3e2
hexbefbf56c549

13124335224137 has 2 divisors, whose sum is σ = 13124335224138. Its totient is φ = 13124335224136.

The previous prime is 13124335224041. The next prime is 13124335224157. The reversal of 13124335224137 is 73142253342131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10202249257216 + 2922085966921 = 3194096^2 + 1709411^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13124335224137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13124335224094 and 13124335224103.

It is not a weakly prime, because it can be changed into another prime (13124335224157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562167612068 + 6562167612069.

It is an arithmetic number, because the mean of its divisors is an integer number (6562167612069).

Almost surely, 213124335224137 is an apocalyptic number.

It is an amenable number.

13124335224137 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124335224137 is an equidigital number, since it uses as much as digits as its factorization.

13124335224137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 362880, while the sum is 41.

Adding to 13124335224137 its reverse (73142253342131), we get a palindrome (86266588566268).

The spelling of 13124335224137 in words is "thirteen trillion, one hundred twenty-four billion, three hundred thirty-five million, two hundred twenty-four thousand, one hundred thirty-seven".