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13124351153 is a prime number
BaseRepresentation
bin11000011100100010…
…11011010010110001
31020212122210010011202
430032101123102301
5203334313214103
610010152220545
7643143100304
oct141621332261
936778703152
1013124351153
115625399301
12266339a755
131312090274
148c7098b3b
1551c316988
hex30e45b4b1

13124351153 has 2 divisors, whose sum is σ = 13124351154. Its totient is φ = 13124351152.

The previous prime is 13124351077. The next prime is 13124351159. The reversal of 13124351153 is 35115342131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13054662049 + 69689104 = 114257^2 + 8348^2 .

It is an emirp because it is prime and its reverse (35115342131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13124351153 is a prime.

It is not a weakly prime, because it can be changed into another prime (13124351159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562175576 + 6562175577.

It is an arithmetic number, because the mean of its divisors is an integer number (6562175577).

Almost surely, 213124351153 is an apocalyptic number.

It is an amenable number.

13124351153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124351153 is an equidigital number, since it uses as much as digits as its factorization.

13124351153 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5400, while the sum is 29.

Adding to 13124351153 its reverse (35115342131), we get a palindrome (48239693284).

The spelling of 13124351153 in words is "thirteen billion, one hundred twenty-four million, three hundred fifty-one thousand, one hundred fifty-three".