Base | Representation |
---|---|
bin | 1011111011111100001111… |
… | …1011111000010000001011 |
3 | 1201110200101212021101220102 |
4 | 2332333003323320100023 |
5 | 3210012244024441212 |
6 | 43525134412520015 |
7 | 2523131113151426 |
oct | 276770373702013 |
9 | 51420355241812 |
10 | 13124412343307 |
11 | 4200039684731 |
12 | 157b72318000b |
13 | 74281c037ac5 |
14 | 33532137a9bd |
15 | 17b5e1bb35c2 |
hex | befc3ef840b |
13124412343307 has 2 divisors, whose sum is σ = 13124412343308. Its totient is φ = 13124412343306.
The previous prime is 13124412343169. The next prime is 13124412343333. The reversal of 13124412343307 is 70334321442131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13124412343307 is a prime.
It is not a weakly prime, because it can be changed into another prime (13124412343337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562206171653 + 6562206171654.
It is an arithmetic number, because the mean of its divisors is an integer number (6562206171654).
Almost surely, 213124412343307 is an apocalyptic number.
13124412343307 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124412343307 is an equidigital number, since it uses as much as digits as its factorization.
13124412343307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145152, while the sum is 38.
Adding to 13124412343307 its reverse (70334321442131), we get a palindrome (83458733785438).
The spelling of 13124412343307 in words is "thirteen trillion, one hundred twenty-four billion, four hundred twelve million, three hundred forty-three thousand, three hundred seven".
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