13124414000403 has 12 divisors (see below), whose sum is σ = 18958197281400. Its totient is φ = 8749281460416.

The previous prime is 13124414000393. The next prime is 13124414000413. The reversal of 13124414000403 is 30400041442131.

13124414000403 is a `hidden beast` number, since 1 + 3 + 1 + 244 + 14 + 0 + 0 + 0 + 403 = 666.

13124414000403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (13124414000393) and next prime (13124414000413).

It is not a de Polignac number, because 13124414000403 - 2¹⁸ = 13124413738259 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13124414000413) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 27069126 + ... + 27549707.

It is an arithmetic number, because the mean of its divisors is an integer number (1579849773450).

Almost surely, 2^{13124414000403} is an apocalyptic number.

13124414000403 is a deficient number, since it is larger than the sum of its proper divisors (5833783280997).

13124414000403 is a wasteful number, since it uses less digits than its factorization.

13124414000403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54645538 (or 54645535 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 13124414000403 its reverse (30400041442131), we get a palindrome (43524455442534).

The spelling of 13124414000403 in words is "thirteen trillion, one hundred twenty-four billion, four hundred fourteen million, four hundred three", and thus it is an aban number.