13124443033113 has 4 divisors (see below), whose sum is σ = 17499257377488. Its totient is φ = 8749628688740.

The previous prime is 13124443033111. The next prime is 13124443033157. The reversal of 13124443033113 is 31133034442131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13124443033113 - 2¹ = 13124443033111 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13124443033111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2187407172183 + ... + 2187407172188.

It is an arithmetic number, because the mean of its divisors is an integer number (4374814344372).

Almost surely, 2^{13124443033113} is an apocalyptic number.

It is an amenable number.

13124443033113 is a deficient number, since it is larger than the sum of its proper divisors (4374814344375).

13124443033113 is an equidigital number, since it uses as much as digits as its factorization.

13124443033113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4374814344374.

The product of its (nonzero) digits is 31104, while the sum is 33.

Adding to 13124443033113 its reverse (31133034442131), we get a palindrome (44257477475244).

The spelling of 13124443033113 in words is "thirteen trillion, one hundred twenty-four billion, four hundred forty-three million, thirty-three thousand, one hundred thirteen".