Base | Representation |
---|---|
bin | 10011000110010111110… |
… | …001000011000101111011 |
3 | 11122110211011110102121102 |
4 | 103012113301003011323 |
5 | 133001010334230434 |
6 | 2442543115002015 |
7 | 163553152325363 |
oct | 23062761030573 |
9 | 4573734412542 |
10 | 1312511242619 |
11 | 4666a6419a25 |
12 | 19245943930b |
13 | 96a0014c395 |
14 | 477510479a3 |
15 | 2421c4d007e |
hex | 13197c4317b |
1312511242619 has 2 divisors, whose sum is σ = 1312511242620. Its totient is φ = 1312511242618.
The previous prime is 1312511242579. The next prime is 1312511242649. The reversal of 1312511242619 is 9162421152131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1312511242619 - 236 = 1243791765883 is a prime.
It is a super-2 number, since 2×13125112426192 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1312511242649) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656255621309 + 656255621310.
It is an arithmetic number, because the mean of its divisors is an integer number (656255621310).
Almost surely, 21312511242619 is an apocalyptic number.
1312511242619 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312511242619 is an equidigital number, since it uses as much as digits as its factorization.
1312511242619 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 25920, while the sum is 38.
The spelling of 1312511242619 in words is "one trillion, three hundred twelve billion, five hundred eleven million, two hundred forty-two thousand, six hundred nineteen".
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