Base | Representation |
---|---|
bin | 10011000110010111111… |
… | …101001111110011011011 |
3 | 11122110211101110220011011 |
4 | 103012113331033303123 |
5 | 133001012144043121 |
6 | 2442543311314351 |
7 | 163553221444366 |
oct | 23062775176333 |
9 | 4573741426134 |
10 | 1312514440411 |
11 | 4666a8203529 |
12 | 19245a51b9b7 |
13 | 96a009cba75 |
14 | 4775163b0dd |
15 | 2421c9127e1 |
hex | 13197f4fcdb |
1312514440411 has 2 divisors, whose sum is σ = 1312514440412. Its totient is φ = 1312514440410.
The previous prime is 1312514440399. The next prime is 1312514440421. The reversal of 1312514440411 is 1140444152131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1312514440411 - 215 = 1312514407643 is a prime.
It is not a weakly prime, because it can be changed into another prime (1312514440421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656257220205 + 656257220206.
It is an arithmetic number, because the mean of its divisors is an integer number (656257220206).
Almost surely, 21312514440411 is an apocalyptic number.
1312514440411 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312514440411 is an equidigital number, since it uses as much as digits as its factorization.
1312514440411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 31.
Adding to 1312514440411 its reverse (1140444152131), we get a palindrome (2452958592542).
The spelling of 1312514440411 in words is "one trillion, three hundred twelve billion, five hundred fourteen million, four hundred forty thousand, four hundred eleven".
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