Base | Representation |
---|---|
bin | 10011000110011000010… |
… | …100100110010110000001 |
3 | 11122110211210222220110111 |
4 | 103012120110212112001 |
5 | 133001020230441144 |
6 | 2442544050431321 |
7 | 163553324461624 |
oct | 23063024462601 |
9 | 4573753886414 |
10 | 1312520562049 |
11 | 466700704834 |
12 | 192460592541 |
13 | 96a02063238 |
14 | 47752391dbb |
15 | 2421d221534 |
hex | 13198526581 |
1312520562049 has 2 divisors, whose sum is σ = 1312520562050. Its totient is φ = 1312520562048.
The previous prime is 1312520562019. The next prime is 1312520562127. The reversal of 1312520562049 is 9402650252131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 786293639824 + 526226922225 = 886732^2 + 725415^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1312520562049 is a prime.
It is not a weakly prime, because it can be changed into another prime (1312520562019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656260281024 + 656260281025.
It is an arithmetic number, because the mean of its divisors is an integer number (656260281025).
Almost surely, 21312520562049 is an apocalyptic number.
It is an amenable number.
1312520562049 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312520562049 is an equidigital number, since it uses as much as digits as its factorization.
1312520562049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 40.
The spelling of 1312520562049 in words is "one trillion, three hundred twelve billion, five hundred twenty million, five hundred sixty-two thousand, forty-nine".
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