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13125251450153 = 131091001239717
BaseRepresentation
bin1011111011111111010111…
…1100110100010100101001
31201110202120100012110002202
42332333311330310110221
53210021003332401103
643525353545505545
72523160652353163
oct276776574642451
951422510173082
1013125251450153
11420042a2a6067
12157b9181a22b5
13742923b30b2b
143353a09a5933
1517b6406b2988
hexbeff5f34529

13125251450153 has 4 divisors (see below), whose sum is σ = 13126252702980. Its totient is φ = 13124250197328.

The previous prime is 13125251450147. The next prime is 13125251450209. The reversal of 13125251450153 is 35105415252131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9910986941584 + 3214264508569 = 3148172^2 + 1792837^2 .

It is a cyclic number.

It is not a de Polignac number, because 13125251450153 - 26 = 13125251450089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13125251450453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500606750 + ... + 500632967.

It is an arithmetic number, because the mean of its divisors is an integer number (3281563175745).

Almost surely, 213125251450153 is an apocalyptic number.

It is an amenable number.

13125251450153 is a deficient number, since it is larger than the sum of its proper divisors (1001252827).

13125251450153 is a wasteful number, since it uses less digits than its factorization.

13125251450153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1001252826.

The product of its (nonzero) digits is 90000, while the sum is 38.

The spelling of 13125251450153 in words is "thirteen trillion, one hundred twenty-five billion, two hundred fifty-one million, four hundred fifty thousand, one hundred fifty-three".

Divisors: 1 13109 1001239717 13125251450153