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13125284713 is a prime number
BaseRepresentation
bin11000011100101001…
…11111001101101001
31020212201112112210001
430032110333031221
5203340033102323
610010224223001
7643154036122
oct141624771551
936781475701
1013125284713
115625976742
12266376aa61
131312329178
148c725d049
1551c44d3ad
hex30e53f369

13125284713 has 2 divisors, whose sum is σ = 13125284714. Its totient is φ = 13125284712.

The previous prime is 13125284687. The next prime is 13125284723. The reversal of 13125284713 is 31748252131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7780651264 + 5344633449 = 88208^2 + 73107^2 .

It is a cyclic number.

It is not a de Polignac number, because 13125284713 - 25 = 13125284681 is a prime.

It is a super-2 number, since 2×131252847132 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13125284723) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562642356 + 6562642357.

It is an arithmetic number, because the mean of its divisors is an integer number (6562642357).

Almost surely, 213125284713 is an apocalyptic number.

It is an amenable number.

13125284713 is a deficient number, since it is larger than the sum of its proper divisors (1).

13125284713 is an equidigital number, since it uses as much as digits as its factorization.

13125284713 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 40320, while the sum is 37.

The spelling of 13125284713 in words is "thirteen billion, one hundred twenty-five million, two hundred eighty-four thousand, seven hundred thirteen".