Base | Representation |
---|---|
bin | 11000011100101001… |
… | …11111001101101001 |
3 | 1020212201112112210001 |
4 | 30032110333031221 |
5 | 203340033102323 |
6 | 10010224223001 |
7 | 643154036122 |
oct | 141624771551 |
9 | 36781475701 |
10 | 13125284713 |
11 | 5625976742 |
12 | 266376aa61 |
13 | 1312329178 |
14 | 8c725d049 |
15 | 51c44d3ad |
hex | 30e53f369 |
13125284713 has 2 divisors, whose sum is σ = 13125284714. Its totient is φ = 13125284712.
The previous prime is 13125284687. The next prime is 13125284723. The reversal of 13125284713 is 31748252131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7780651264 + 5344633449 = 88208^2 + 73107^2 .
It is a cyclic number.
It is not a de Polignac number, because 13125284713 - 25 = 13125284681 is a prime.
It is a super-2 number, since 2×131252847132 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13125284723) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562642356 + 6562642357.
It is an arithmetic number, because the mean of its divisors is an integer number (6562642357).
Almost surely, 213125284713 is an apocalyptic number.
It is an amenable number.
13125284713 is a deficient number, since it is larger than the sum of its proper divisors (1).
13125284713 is an equidigital number, since it uses as much as digits as its factorization.
13125284713 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 40320, while the sum is 37.
The spelling of 13125284713 in words is "thirteen billion, one hundred twenty-five million, two hundred eighty-four thousand, seven hundred thirteen".
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