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1312530431051 = 7391947844947
BaseRepresentation
bin10011000110011000111…
…010001111110001001011
311122110212111120022012002
4103012120322033301023
5133001030242243201
62442545042141215
7163553504404340
oct23063072176113
94573774508162
101312530431051
11466706235534
1219246395180b
1396a0410a298
14477538007c7
152421e02076b
hex13198e8fc4b

1312530431051 has 8 divisors (see below), whose sum is σ = 1500417569280. Its totient is φ = 1124738990568.

The previous prime is 1312530430993. The next prime is 1312530431117. The reversal of 1312530431051 is 1501340352131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1312530431051 is a prime.

It is a super-2 number, since 2×13125304310512 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1312530431651) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23895041 + ... + 23949906.

It is an arithmetic number, because the mean of its divisors is an integer number (187552196160).

Almost surely, 21312530431051 is an apocalyptic number.

1312530431051 is a deficient number, since it is larger than the sum of its proper divisors (187887138229).

1312530431051 is an equidigital number, since it uses as much as digits as its factorization.

1312530431051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47848873.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 1312530431051 its reverse (1501340352131), we get a palindrome (2813870783182).

The spelling of 1312530431051 in words is "one trillion, three hundred twelve billion, five hundred thirty million, four hundred thirty-one thousand, fifty-one".

Divisors: 1 7 3919 27433 47844947 334914629 187504347293 1312530431051