Base | Representation |
---|---|
bin | 1011111011111111101001… |
… | …0111011011000000110001 |
3 | 1201110202202111121020222112 |
4 | 2332333322113123000301 |
5 | 3210021131314030413 |
6 | 43525405153415105 |
7 | 2523162542143634 |
oct | 276777227330061 |
9 | 51422674536875 |
10 | 13125325533233 |
11 | 42004680a5851 |
12 | 157b938b6a495 |
13 | 74293629bc84 |
14 | 3353aa76bc1b |
15 | 17b646e482a8 |
hex | beffa5db031 |
13125325533233 has 8 divisors (see below), whose sum is σ = 13145151814656. Its totient is φ = 13105508666400.
The previous prime is 13125325533179. The next prime is 13125325533311. The reversal of 13125325533233 is 33233552352131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13125325533233 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13125325533533) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 439253 + ... + 5142333.
It is an arithmetic number, because the mean of its divisors is an integer number (1643143976832).
Almost surely, 213125325533233 is an apocalyptic number.
It is an amenable number.
13125325533233 is a deficient number, since it is larger than the sum of its proper divisors (19826281423).
13125325533233 is an equidigital number, since it uses as much as digits as its factorization.
13125325533233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4707295.
The product of its digits is 729000, while the sum is 41.
Adding to 13125325533233 its reverse (33233552352131), we get a palindrome (46358877885364).
The spelling of 13125325533233 in words is "thirteen trillion, one hundred twenty-five billion, three hundred twenty-five million, five hundred thirty-three thousand, two hundred thirty-three".
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