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13125404434435 = 58595171590983
BaseRepresentation
bin1011111011111111111100…
…0100011010000000000011
31201110202222000001212002021
42332333333010122000003
53210021312013400220
643525421052502311
72523164520612406
oct276777704320003
951422860055067
1013125404434435
1142004a8696457
12157b95b47a997
13742949736187
143353b7029d3d
1517b64dd314aa
hexbefff11a003

13125404434435 has 16 divisors (see below), whose sum is σ = 15771897319680. Its totient is φ = 10486053658080.

The previous prime is 13125404434427. The next prime is 13125404434459. The reversal of 13125404434435 is 53443440452131.

It is not a de Polignac number, because 13125404434435 - 23 = 13125404434427 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13125404434391 and 13125404434400.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21913954 + ... + 22504936.

It is an arithmetic number, because the mean of its divisors is an integer number (985743582480).

Almost surely, 213125404434435 is an apocalyptic number.

13125404434435 is a deficient number, since it is larger than the sum of its proper divisors (2646492885245).

13125404434435 is an equidigital number, since it uses as much as digits as its factorization.

13125404434435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 597018.

The product of its (nonzero) digits is 1382400, while the sum is 43.

Adding to 13125404434435 its reverse (53443440452131), we get a palindrome (66568844886566).

The spelling of 13125404434435 in words is "thirteen trillion, one hundred twenty-five billion, four hundred four million, four hundred thirty-four thousand, four hundred thirty-five".

Divisors: 1 5 859 4295 5171 25855 590983 2954915 4441889 22209445 507654397 2538271985 3055973093 15279865465 2625080886887 13125404434435