13125411343081 has 2 divisors, whose sum is σ = 13125411343082. Its totient is φ = 13125411343080.

The previous prime is 13125411343007. The next prime is 13125411343087. The reversal of 13125411343081 is 18034311452131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6603435181225 + 6521976161856 = 2569715^2 + 2553816^2 .

It is a cyclic number.

It is not a de Polignac number, because 13125411343081 - 2¹⁵ = 13125411310313 is a prime.

It is a super-2 number, since 2×13125411343081² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13125411343081.

It is not a weakly prime, because it can be changed into another prime (13125411343087) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562705671540 + 6562705671541.

It is an arithmetic number, because the mean of its divisors is an integer number (6562705671541).

Almost surely, 2^{13125411343081} is an apocalyptic number.

It is an amenable number.

13125411343081 is a deficient number, since it is larger than the sum of its proper divisors (1).

13125411343081 is an equidigital number, since it uses as much as digits as its factorization.

13125411343081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34560, while the sum is 37.

The spelling of 13125411343081 in words is "thirteen trillion, one hundred twenty-five billion, four hundred eleven million, three hundred forty-three thousand, eighty-one".