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13125411343169 is a prime number
BaseRepresentation
bin1011111011111111111101…
…1110110000101101000001
31201110202222111001212002022
42332333333132300231001
53210021320300440134
643525421500531225
72523164633415446
oct276777736605501
951422874055068
1013125411343169
114200501585054
12157b961850b15
1374294acb4998
143353b7d079cd
1517b64e74852e
hexbefff7b0b41

13125411343169 has 2 divisors, whose sum is σ = 13125411343170. Its totient is φ = 13125411343168.

The previous prime is 13125411343123. The next prime is 13125411343207. The reversal of 13125411343169 is 96134311452131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11854166368144 + 1271244975025 = 3442988^2 + 1127495^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13125411343169 is a prime.

It is a super-2 number, since 2×131254113431692 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13125411345169) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562705671584 + 6562705671585.

It is an arithmetic number, because the mean of its divisors is an integer number (6562705671585).

Almost surely, 213125411343169 is an apocalyptic number.

It is an amenable number.

13125411343169 is a deficient number, since it is larger than the sum of its proper divisors (1).

13125411343169 is an equidigital number, since it uses as much as digits as its factorization.

13125411343169 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 233280, while the sum is 44.

The spelling of 13125411343169 in words is "thirteen trillion, one hundred twenty-five billion, four hundred eleven million, three hundred forty-three thousand, one hundred sixty-nine".