Base | Representation |
---|---|
bin | 1011111100000000010110… |
… | …0110110011000110100011 |
3 | 1201110210020122110010101202 |
4 | 2333000011212303012203 |
5 | 3210022023103112233 |
6 | 43525440011351415 |
7 | 2523200322066314 |
oct | 277000546630643 |
9 | 51423218403352 |
10 | 13125514113443 |
11 | 4200554598966 |
12 | 157b99015256b |
13 | 7429663883b4 |
14 | 3353c781a60b |
15 | 17b658798be8 |
hex | bf0059b31a3 |
13125514113443 has 2 divisors, whose sum is σ = 13125514113444. Its totient is φ = 13125514113442.
The previous prime is 13125514113431. The next prime is 13125514113461. The reversal of 13125514113443 is 34431141552131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13125514113443 - 216 = 13125514047907 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13125514113397 and 13125514113406.
It is not a weakly prime, because it can be changed into another prime (13125514113403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562757056721 + 6562757056722.
It is an arithmetic number, because the mean of its divisors is an integer number (6562757056722).
Almost surely, 213125514113443 is an apocalyptic number.
13125514113443 is a deficient number, since it is larger than the sum of its proper divisors (1).
13125514113443 is an equidigital number, since it uses as much as digits as its factorization.
13125514113443 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 86400, while the sum is 38.
Adding to 13125514113443 its reverse (34431141552131), we get a palindrome (47556655665574).
The spelling of 13125514113443 in words is "thirteen trillion, one hundred twenty-five billion, five hundred fourteen million, one hundred thirteen thousand, four hundred forty-three".
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