Base | Representation |
---|---|
bin | 1011111100000011000001… |
… | …0101011111011000010001 |
3 | 1201110212002121101120001222 |
4 | 2333000300111133120101 |
5 | 3210030010113341442 |
6 | 43530035100534425 |
7 | 2523224145355343 |
oct | 277006025373021 |
9 | 51425077346058 |
10 | 13126230996497 |
11 | 42008922197a3 |
12 | 157bb50251415 |
13 | 742a4ba59258 |
14 | 335454b0b293 |
15 | 17b69b6a38d2 |
hex | bf03055f611 |
13126230996497 has 2 divisors, whose sum is σ = 13126230996498. Its totient is φ = 13126230996496.
The previous prime is 13126230996491. The next prime is 13126230996521. The reversal of 13126230996497 is 79469903262131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10383500854336 + 2742730142161 = 3222344^2 + 1656119^2 .
It is an emirp because it is prime and its reverse (79469903262131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13126230996497 - 210 = 13126230995473 is a prime.
It is not a weakly prime, because it can be changed into another prime (13126230996491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6563115498248 + 6563115498249.
It is an arithmetic number, because the mean of its divisors is an integer number (6563115498249).
Almost surely, 213126230996497 is an apocalyptic number.
It is an amenable number.
13126230996497 is a deficient number, since it is larger than the sum of its proper divisors (1).
13126230996497 is an equidigital number, since it uses as much as digits as its factorization.
13126230996497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26453952, while the sum is 62.
The spelling of 13126230996497 in words is "thirteen trillion, one hundred twenty-six billion, two hundred thirty million, nine hundred ninety-six thousand, four hundred ninety-seven".
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