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1312736052531 = 3437578684177
BaseRepresentation
bin10011000110100101001…
…010101000010100110011
311122111101211110221211110
4103012211022220110303
5133001440412140111
62443021305244403
7163561552224021
oct23064512502463
94574354427743
101312736052531
11466801307a42
12192500793703
1396a378b21b7
1447772c47711
15242320da5a6
hex131a52a8533

1312736052531 has 4 divisors (see below), whose sum is σ = 1750314736712. Its totient is φ = 875157368352.

The previous prime is 1312736052521. The next prime is 1312736052547. The reversal of 1312736052531 is 1352506372131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1312736052531 - 210 = 1312736051507 is a prime.

It is a super-2 number, since 2×13127360525312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1312736052531.

It is not an unprimeable number, because it can be changed into a prime (1312736052521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218789342086 + ... + 218789342091.

It is an arithmetic number, because the mean of its divisors is an integer number (437578684178).

Almost surely, 21312736052531 is an apocalyptic number.

1312736052531 is a deficient number, since it is larger than the sum of its proper divisors (437578684181).

1312736052531 is an equidigital number, since it uses as much as digits as its factorization.

1312736052531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 437578684180.

The product of its (nonzero) digits is 113400, while the sum is 39.

The spelling of 1312736052531 in words is "one trillion, three hundred twelve billion, seven hundred thirty-six million, fifty-two thousand, five hundred thirty-one".

Divisors: 1 3 437578684177 1312736052531