Base | Representation |
---|---|
bin | 11000011100111010… |
… | …00100100101010001 |
3 | 1020212212112012200212 |
4 | 30032131010211101 |
5 | 203341103410412 |
6 | 10010341453505 |
7 | 643211043311 |
oct | 141635044521 |
9 | 36785465625 |
10 | 13127403857 |
11 | 56270938a7 |
12 | 2664411295 |
13 | 13128bb8b9 |
14 | 8c7651441 |
15 | 51c71b222 |
hex | 30e744951 |
13127403857 has 2 divisors, whose sum is σ = 13127403858. Its totient is φ = 13127403856.
The previous prime is 13127403803. The next prime is 13127403899. The reversal of 13127403857 is 75830472131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9690630481 + 3436773376 = 98441^2 + 58624^2 .
It is a cyclic number.
It is not a de Polignac number, because 13127403857 - 214 = 13127387473 is a prime.
It is not a weakly prime, because it can be changed into another prime (13127406857) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6563701928 + 6563701929.
It is an arithmetic number, because the mean of its divisors is an integer number (6563701929).
Almost surely, 213127403857 is an apocalyptic number.
It is an amenable number.
13127403857 is a deficient number, since it is larger than the sum of its proper divisors (1).
13127403857 is an equidigital number, since it uses as much as digits as its factorization.
13127403857 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 141120, while the sum is 41.
Adding to 13127403857 its reverse (75830472131), we get a palindrome (88957875988).
The spelling of 13127403857 in words is "thirteen billion, one hundred twenty-seven million, four hundred three thousand, eight hundred fifty-seven".
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