Base | Representation |
---|---|
bin | 11000011100111011… |
… | …00110101011000011 |
3 | 1020212212210022020111 |
4 | 30032131212223003 |
5 | 203341122342431 |
6 | 10010344452151 |
7 | 643212164356 |
oct | 141635465303 |
9 | 36785708214 |
10 | 13127543491 |
11 | 56271797a7 |
12 | 266447a057 |
13 | 131293a31a |
14 | 8c768a29d |
15 | 51c7477b1 |
hex | 30e766ac3 |
13127543491 has 8 divisors (see below), whose sum is σ = 13345392368. Its totient is φ = 12909780000.
The previous prime is 13127543461. The next prime is 13127543563. The reversal of 13127543491 is 19434572131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13127543491 - 25 = 13127543459 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13127543461) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 338521 + ... + 375301.
It is an arithmetic number, because the mean of its divisors is an integer number (1668174046).
Almost surely, 213127543491 is an apocalyptic number.
13127543491 is a deficient number, since it is larger than the sum of its proper divisors (217848877).
13127543491 is an equidigital number, since it uses as much as digits as its factorization.
13127543491 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42693.
The product of its digits is 90720, while the sum is 40.
The spelling of 13127543491 in words is "thirteen billion, one hundred twenty-seven million, five hundred forty-three thousand, four hundred ninety-one".
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