Base | Representation |
---|---|
bin | 10011000110110100111… |
… | …101011100110110101011 |
3 | 11122112002022002100212202 |
4 | 103012310331130312223 |
5 | 133003011231030011 |
6 | 2443103452530415 |
7 | 163601250431144 |
oct | 23066475346653 |
9 | 4575068070782 |
10 | 1313001033131 |
11 | 466927942877 |
12 | 192575480a0b |
13 | 96a7a76b458 |
14 | 4779a102acb |
15 | 2424a4cd23b |
hex | 131b4f5cdab |
1313001033131 has 2 divisors, whose sum is σ = 1313001033132. Its totient is φ = 1313001033130.
The previous prime is 1313001033119. The next prime is 1313001033199. The reversal of 1313001033131 is 1313301003131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1313001033131 is a prime.
It is a super-2 number, since 2×13130010331312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1313001033101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656500516565 + 656500516566.
It is an arithmetic number, because the mean of its divisors is an integer number (656500516566).
Almost surely, 21313001033131 is an apocalyptic number.
1313001033131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313001033131 is an equidigital number, since it uses as much as digits as its factorization.
1313001033131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 20.
Adding to 1313001033131 its reverse (1313301003131), we get a palindrome (2626302036262).
The spelling of 1313001033131 in words is "one trillion, three hundred thirteen billion, one million, thirty-three thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •