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131300111233 = 833956939979
BaseRepresentation
bin111101001001000011…
…0001011001110000001
3110112220112022201221201
41322102012023032001
54122400312024413
6140152441021201
712325511350054
oct1722206131601
9415815281851
10131300111233
1150758542a25
1221544184801
13c4c634b315
1464d8018a9b
1536370769dd
hex1e9218b381

131300111233 has 8 divisors (see below), whose sum is σ = 132888722400. Its totient is φ = 129711659328.

The previous prime is 131300111227. The next prime is 131300111273. The reversal of 131300111233 is 332111003131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131300111233 - 225 = 131266556801 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131300111233.

It is not an unprimeable number, because it can be changed into a prime (131300111273) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3264238 + ... + 3304216.

It is an arithmetic number, because the mean of its divisors is an integer number (16611090300).

Almost surely, 2131300111233 is an apocalyptic number.

It is an amenable number.

131300111233 is a deficient number, since it is larger than the sum of its proper divisors (1588611167).

131300111233 is an equidigital number, since it uses as much as digits as its factorization.

131300111233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79631.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 131300111233 its reverse (332111003131), we get a palindrome (463411114364).

The spelling of 131300111233 in words is "one hundred thirty-one billion, three hundred million, one hundred eleven thousand, two hundred thirty-three".

Divisors: 1 83 39569 39979 3284227 3318257 1581929051 131300111233