Base | Representation |
---|---|
bin | 10011000110110100111… |
… | …101110100110001101010 |
3 | 11122112002022021100021202 |
4 | 103012310331310301222 |
5 | 133003011242143424 |
6 | 2443103455004202 |
7 | 163601251316621 |
oct | 23066475646152 |
9 | 4575068240252 |
10 | 1313001131114 |
11 | 4669279aa452 |
12 | 192575509662 |
13 | 96a7a7a3c2a |
14 | 4779a12a6b8 |
15 | 2424a4ec2ae |
hex | 131b4f74c6a |
1313001131114 has 4 divisors (see below), whose sum is σ = 1969501696674. Its totient is φ = 656500565556.
The previous prime is 1313001131087. The next prime is 1313001131131. The reversal of 1313001131114 is 4111311003131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1131978963025 + 181022168089 = 1063945^2 + 425467^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 328250282777 + ... + 328250282780.
Almost surely, 21313001131114 is an apocalyptic number.
1313001131114 is a deficient number, since it is larger than the sum of its proper divisors (656500565560).
1313001131114 is an equidigital number, since it uses as much as digits as its factorization.
1313001131114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 656500565559.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 1313001131114 its reverse (4111311003131), we get a palindrome (5424312134245).
The spelling of 1313001131114 in words is "one trillion, three hundred thirteen billion, one million, one hundred thirty-one thousand, one hundred fourteen".
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