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13130011441 = 16778622823
BaseRepresentation
bin11000011101001110…
…00001001100110001
31020220001102200122001
430032213001030301
5203342240331231
610010513414001
7643242153511
oct141647011461
936801380561
1013130011441
115628604a28
12266526a301
1313132c2751
148c7b2d841
1551ca83b61
hex30e9c1331

13130011441 has 4 divisors (see below), whose sum is σ = 13208634432. Its totient is φ = 13051388452.

The previous prime is 13130011423. The next prime is 13130011451. The reversal of 13130011441 is 14411003131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13130011441 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13130011451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39311245 + ... + 39311578.

It is an arithmetic number, because the mean of its divisors is an integer number (3302158608).

Almost surely, 213130011441 is an apocalyptic number.

It is an amenable number.

13130011441 is a deficient number, since it is larger than the sum of its proper divisors (78622991).

13130011441 is an equidigital number, since it uses as much as digits as its factorization.

13130011441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 78622990.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13130011441 its reverse (14411003131), we get a palindrome (27541014572).

The spelling of 13130011441 in words is "thirteen billion, one hundred thirty million, eleven thousand, four hundred forty-one".

Divisors: 1 167 78622823 13130011441