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1313001202003 = 1522786228489
BaseRepresentation
bin10011000110110100111…
…110000110000101010011
311122112002022101221112021
4103012310332012011103
5133003011301431003
62443103500312311
7163601252033401
oct23066476060523
94575068357467
101313001202003
11466927a48737
12192575542697
1396a7a7ca28a
144779a148471
152424a5132bd
hex131b4f86153

1313001202003 has 4 divisors (see below), whose sum is σ = 1313087445720. Its totient is φ = 1312914958288.

The previous prime is 1313001201971. The next prime is 1313001202027. The reversal of 1313001202003 is 3002021003131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1313001202003 - 25 = 1313001201971 is a prime.

It is a super-2 number, since 2×13130012020032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313001202043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43099018 + ... + 43129471.

It is an arithmetic number, because the mean of its divisors is an integer number (328271861430).

Almost surely, 21313001202003 is an apocalyptic number.

1313001202003 is a deficient number, since it is larger than the sum of its proper divisors (86243717).

1313001202003 is an equidigital number, since it uses as much as digits as its factorization.

1313001202003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 86243716.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 1313001202003 its reverse (3002021003131), we get a palindrome (4315022205134).

The spelling of 1313001202003 in words is "one trillion, three hundred thirteen billion, one million, two hundred two thousand, three".

Divisors: 1 15227 86228489 1313001202003