Base | Representation |
---|---|
bin | 111101001001000011… |
… | …0001110000110000011 |
3 | 110112220112100100002221 |
4 | 1322102012032012003 |
5 | 4122400312414021 |
6 | 140152441151511 |
7 | 12325511426311 |
oct | 1722206160603 |
9 | 415815310087 |
10 | 131300123011 |
11 | 50758550862 |
12 | 2154418b597 |
13 | c4c63537a5 |
14 | 64d801d0b1 |
15 | 363707a241 |
hex | 1e9218e183 |
131300123011 has 2 divisors, whose sum is σ = 131300123012. Its totient is φ = 131300123010.
The previous prime is 131300122981. The next prime is 131300123051. The reversal of 131300123011 is 110321003131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131300123011 - 27 = 131300122883 is a prime.
It is a super-2 number, since 2×1313001230112 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131300123051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65650061505 + 65650061506.
It is an arithmetic number, because the mean of its divisors is an integer number (65650061506).
Almost surely, 2131300123011 is an apocalyptic number.
131300123011 is a deficient number, since it is larger than the sum of its proper divisors (1).
131300123011 is an equidigital number, since it uses as much as digits as its factorization.
131300123011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 131300123011 its reverse (110321003131), we get a palindrome (241621126142).
The spelling of 131300123011 in words is "one hundred thirty-one billion, three hundred million, one hundred twenty-three thousand, eleven".
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