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13130023211203 = 638910859189253
BaseRepresentation
bin1011111100010001001001…
…0111101001000011000011
31201111012212220010000200111
42333010102113221003003
53210110241420224303
643531503245132151
72523420133561033
oct277042227510303
951435786100614
1013130023211203
114202458892838
12158082a25a057
137432045c8b92
143356d46138c3
1517b81e582b6d
hexbf1125e90c3

13130023211203 has 8 divisors (see below), whose sum is σ = 13133357031600. Its totient is φ = 13126689803808.

The previous prime is 13130023211147. The next prime is 13130023211209. The reversal of 13130023211203 is 30211232003131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13130023211203 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13130023211209) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 69283525 + ... + 69472777.

It is an arithmetic number, because the mean of its divisors is an integer number (1641669628950).

Almost surely, 213130023211203 is an apocalyptic number.

13130023211203 is a deficient number, since it is larger than the sum of its proper divisors (3333820397).

13130023211203 is a wasteful number, since it uses less digits than its factorization.

13130023211203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 206501.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 13130023211203 its reverse (30211232003131), we get a palindrome (43341255214334).

The spelling of 13130023211203 in words is "thirteen trillion, one hundred thirty billion, twenty-three million, two hundred eleven thousand, two hundred three".

Divisors: 1 6389 10859 189253 69378151 1209137417 2055098327 13130023211203