Base | Representation |
---|---|
bin | 11101110110101010111101… |
… | …100010101101010101000011 |
3 | 122012220012002202202012220201 |
4 | 131312222331202231111003 |
5 | 114202211034014343412 |
6 | 1143130312231350031 |
7 | 36441064404253102 |
oct | 3566527542552503 |
9 | 565805082665821 |
10 | 131300330231107 |
11 | 38922180471994 |
12 | 12886a72b22317 |
13 | 583574cc0363b |
14 | 245cd8154a039 |
15 | 102a65249ee57 |
hex | 776abd8ad543 |
131300330231107 has 2 divisors, whose sum is σ = 131300330231108. Its totient is φ = 131300330231106.
The previous prime is 131300330231101. The next prime is 131300330231111. The reversal of 131300330231107 is 701132033003131.
It is a strong prime.
It is an emirp because it is prime and its reverse (701132033003131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131300330231107 - 239 = 130750574417219 is a prime.
It is not a weakly prime, because it can be changed into another prime (131300330231101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65650165115553 + 65650165115554.
It is an arithmetic number, because the mean of its divisors is an integer number (65650165115554).
Almost surely, 2131300330231107 is an apocalyptic number.
131300330231107 is a deficient number, since it is larger than the sum of its proper divisors (1).
131300330231107 is an equidigital number, since it uses as much as digits as its factorization.
131300330231107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3402, while the sum is 28.
Adding to 131300330231107 its reverse (701132033003131), we get a palindrome (832432363234238).
The spelling of 131300330231107 in words is "one hundred thirty-one trillion, three hundred billion, three hundred thirty million, two hundred thirty-one thousand, one hundred seven".
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