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13130034123211 = 16018201145611
BaseRepresentation
bin1011111100010001001100…
…0001010001000111001011
31201111012220122122102010221
42333010103001101013023
53210110302213420321
643531504315050511
72523420325406335
oct277042301210713
951435818572127
1013130034123211
114202463a66125
121580831a40a37
137432069498a5
143356d5c54455
1517b8204dae41
hexbf1130511cb

13130034123211 has 4 divisors (see below), whose sum is σ = 13138235270424. Its totient is φ = 13121832976000.

The previous prime is 13130034123109. The next prime is 13130034123287. The reversal of 13130034123211 is 11232143003131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13130034123211 - 227 = 13129899905483 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13130034123511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4100571205 + ... + 4100574406.

It is an arithmetic number, because the mean of its divisors is an integer number (3284558817606).

Almost surely, 213130034123211 is an apocalyptic number.

13130034123211 is a deficient number, since it is larger than the sum of its proper divisors (8201147213).

13130034123211 is an equidigital number, since it uses as much as digits as its factorization.

13130034123211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8201147212.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13130034123211 its reverse (11232143003131), we get a palindrome (24362177126342).

The spelling of 13130034123211 in words is "thirteen trillion, one hundred thirty billion, thirty-four million, one hundred twenty-three thousand, two hundred eleven".

Divisors: 1 1601 8201145611 13130034123211