13130089241 has 2 divisors, whose sum is σ = 13130089242. Its totient is φ = 13130089240.

The previous prime is 13130089223. The next prime is 13130089253. The reversal of 13130089241 is 14298003131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11901937216 + 1228152025 = 109096^2 + 35045^2 .

It is an emirp because it is prime and its reverse (14298003131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13130089241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13130089198 and 13130089207.

It is not a weakly prime, because it can be changed into another prime (13130089201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565044620 + 6565044621.

It is an arithmetic number, because the mean of its divisors is an integer number (6565044621).

Almost surely, 2^13130089241 is an apocalyptic number.

It is an amenable number.

13130089241 is a deficient number, since it is larger than the sum of its proper divisors (1).

13130089241 is an equidigital number, since it uses as much as digits as its factorization.

13130089241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 32.

The spelling of 13130089241 in words is "thirteen billion, one hundred thirty million, eighty-nine thousand, two hundred forty-one".