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13130095969 is a prime number
BaseRepresentation
bin11000011101001110…
…10101110101100001
31020220001120222120201
430032213111311201
5203342301032334
610010515305201
7643242655114
oct141647256541
936801528521
1013130095969
115628662491
1226652ab201
131313322073
148c7b5257b
1551ca9dc14
hex30e9d5d61

13130095969 has 2 divisors, whose sum is σ = 13130095970. Its totient is φ = 13130095968.

The previous prime is 13130095961. The next prime is 13130095981. The reversal of 13130095969 is 96959003131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11387450944 + 1742645025 = 106712^2 + 41745^2 .

It is an emirp because it is prime and its reverse (96959003131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13130095969 - 23 = 13130095961 is a prime.

It is a super-2 number, since 2×131300959692 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13130095961) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565047984 + 6565047985.

It is an arithmetic number, because the mean of its divisors is an integer number (6565047985).

Almost surely, 213130095969 is an apocalyptic number.

It is an amenable number.

13130095969 is a deficient number, since it is larger than the sum of its proper divisors (1).

13130095969 is an equidigital number, since it uses as much as digits as its factorization.

13130095969 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 196830, while the sum is 46.

The spelling of 13130095969 in words is "thirteen billion, one hundred thirty million, ninety-five thousand, nine hundred sixty-nine".