Base | Representation |
---|---|
bin | 111101001001000100… |
… | …1101001111001011011 |
3 | 110112220121001002002211 |
4 | 1322102021221321123 |
5 | 4122401030221243 |
6 | 140152512335551 |
7 | 12325522166161 |
oct | 1722211517133 |
9 | 415817032084 |
10 | 131301023323 |
11 | 50759006218 |
12 | 215445445b7 |
13 | c4c65aa512 |
14 | 64d81b5231 |
15 | 36371a6d9d |
hex | 1e92269e5b |
131301023323 has 2 divisors, whose sum is σ = 131301023324. Its totient is φ = 131301023322.
The previous prime is 131301023317. The next prime is 131301023327. The reversal of 131301023323 is 323320103131.
It is a strong prime.
It is an emirp because it is prime and its reverse (323320103131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131301023323 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131301023294 and 131301023303.
It is not a weakly prime, because it can be changed into another prime (131301023327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65650511661 + 65650511662.
It is an arithmetic number, because the mean of its divisors is an integer number (65650511662).
Almost surely, 2131301023323 is an apocalyptic number.
131301023323 is a deficient number, since it is larger than the sum of its proper divisors (1).
131301023323 is an equidigital number, since it uses as much as digits as its factorization.
131301023323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 131301023323 its reverse (323320103131), we get a palindrome (454621126454).
The spelling of 131301023323 in words is "one hundred thirty-one billion, three hundred one million, twenty-three thousand, three hundred twenty-three".
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