13130123113 has 4 divisors (see below), whose sum is σ = 13130409600. Its totient is φ = 13129836628.

The previous prime is 13130123089. The next prime is 13130123159. The reversal of 13130123113 is 31132103131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31132103131 = 47 ⋅662385173.

It is a cyclic number.

It is not a de Polignac number, because 13130123113 - 2²¹ = 13128025961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13130124113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57313 + ... + 171886.

It is an arithmetic number, because the mean of its divisors is an integer number (3282602400).

Almost surely, 2^13130123113 is an apocalyptic number.

It is an amenable number.

13130123113 is a deficient number, since it is larger than the sum of its proper divisors (286487).

13130123113 is an equidigital number, since it uses as much as digits as its factorization.

13130123113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 286486.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 13130123113 its reverse (31132103131), we get a palindrome (44262226244).

The spelling of 13130123113 in words is "thirteen billion, one hundred thirty million, one hundred twenty-three thousand, one hundred thirteen".