Base | Representation |
---|---|
bin | 10011000110110110000… |
… | …110100110110010111011 |
3 | 11122112010122011200002121 |
4 | 103012312012212302323 |
5 | 133003031133212423 |
6 | 2443105415542111 |
7 | 163601602432351 |
oct | 23066606466273 |
9 | 4575118150077 |
10 | 1313020210363 |
11 | 466937750a24 |
12 | 19257b98a937 |
13 | 96a81724224 |
14 | 4779c8957d1 |
15 | 2424c01a45d |
hex | 131b61a6cbb |
1313020210363 has 2 divisors, whose sum is σ = 1313020210364. Its totient is φ = 1313020210362.
The previous prime is 1313020210331. The next prime is 1313020210417. The reversal of 1313020210363 is 3630120203131.
It is a weak prime.
It is an emirp because it is prime and its reverse (3630120203131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1313020210363 - 25 = 1313020210331 is a prime.
It is not a weakly prime, because it can be changed into another prime (1313020220363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656510105181 + 656510105182.
It is an arithmetic number, because the mean of its divisors is an integer number (656510105182).
Almost surely, 21313020210363 is an apocalyptic number.
1313020210363 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313020210363 is an equidigital number, since it uses as much as digits as its factorization.
1313020210363 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1313020210363 its reverse (3630120203131), we get a palindrome (4943140413494).
The spelling of 1313020210363 in words is "one trillion, three hundred thirteen billion, twenty million, two hundred ten thousand, three hundred sixty-three".
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