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13130210010241 is a prime number
BaseRepresentation
bin1011111100010001110110…
…0000001110010010000001
31201111020100220121101210101
42333010131200032102001
53210111132230311431
643531534001002401
72523424562414452
oct277043540162201
951436326541711
1013130210010241
114202544279705
121580880923401
1374323421065c
1433571135b129
1517b830b80961
hexbf11d80e481

13130210010241 has 2 divisors, whose sum is σ = 13130210010242. Its totient is φ = 13130210010240.

The previous prime is 13130210010227. The next prime is 13130210010263. The reversal of 13130210010241 is 14201001203131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13082117520241 + 48092490000 = 3616921^2 + 219300^2 .

It is a cyclic number.

It is not a de Polignac number, because 13130210010241 - 29 = 13130210009729 is a prime.

It is a super-2 number, since 2×131302100102412 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13130210010341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565105005120 + 6565105005121.

It is an arithmetic number, because the mean of its divisors is an integer number (6565105005121).

Almost surely, 213130210010241 is an apocalyptic number.

It is an amenable number.

13130210010241 is a deficient number, since it is larger than the sum of its proper divisors (1).

13130210010241 is an equidigital number, since it uses as much as digits as its factorization.

13130210010241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13130210010241 its reverse (14201001203131), we get a palindrome (27331211213372).

The spelling of 13130210010241 in words is "thirteen trillion, one hundred thirty billion, two hundred ten million, ten thousand, two hundred forty-one".