Base | Representation |
---|---|
bin | 10011000110110110001… |
… | …010000010111011101001 |
3 | 11122112010200212110222002 |
4 | 103012312022002323221 |
5 | 133003031401041131 |
6 | 2443105451140345 |
7 | 163601613206222 |
oct | 23066612027351 |
9 | 4575120773862 |
10 | 1313021112041 |
11 | 466938207411 |
12 | 1925801446b5 |
13 | 96a8197b772 |
14 | 4779ca4c249 |
15 | 2424c1476cb |
hex | 131b6282ee9 |
1313021112041 has 2 divisors, whose sum is σ = 1313021112042. Its totient is φ = 1313021112040.
The previous prime is 1313021111981. The next prime is 1313021112049. The reversal of 1313021112041 is 1402111203131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1291470872041 + 21550240000 = 1136429^2 + 146800^2 .
It is an emirp because it is prime and its reverse (1402111203131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1313021112041 is a prime.
It is not a weakly prime, because it can be changed into another prime (1313021112049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656510556020 + 656510556021.
It is an arithmetic number, because the mean of its divisors is an integer number (656510556021).
Almost surely, 21313021112041 is an apocalyptic number.
It is an amenable number.
1313021112041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313021112041 is an equidigital number, since it uses as much as digits as its factorization.
1313021112041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 1313021112041 its reverse (1402111203131), we get a palindrome (2715132315172).
The spelling of 1313021112041 in words is "one trillion, three hundred thirteen billion, twenty-one million, one hundred twelve thousand, forty-one".
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