Base | Representation |
---|---|
bin | 11101110110101100110100… |
… | …001101110001000110000011 |
3 | 122012220101020112011110020021 |
4 | 131312230310031301012003 |
5 | 114202224123213331321 |
6 | 1143131241553354311 |
7 | 36441164631416155 |
oct | 3566546415610603 |
9 | 565811215143207 |
10 | 131302321230211 |
11 | 38923002320a9a |
12 | 12887329868997 |
13 | 58359a9548b11 |
14 | 245d0cdb40ad5 |
15 | 102a71c185941 |
hex | 776b34371183 |
131302321230211 has 4 divisors (see below), whose sum is σ = 131343314777352. Its totient is φ = 131261327683072.
The previous prime is 131302321230187. The next prime is 131302321230217. The reversal of 131302321230211 is 112032123203131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131302321230211 - 213 = 131302321222019 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131302321230217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20496768766 + ... + 20496775171.
It is an arithmetic number, because the mean of its divisors is an integer number (32835828694338).
Almost surely, 2131302321230211 is an apocalyptic number.
131302321230211 is a deficient number, since it is larger than the sum of its proper divisors (40993547141).
131302321230211 is an equidigital number, since it uses as much as digits as its factorization.
131302321230211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40993547140.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 131302321230211 its reverse (112032123203131), we get a palindrome (243334444433342).
The spelling of 131302321230211 in words is "one hundred thirty-one trillion, three hundred two billion, three hundred twenty-one million, two hundred thirty thousand, two hundred eleven".
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