Base | Representation |
---|---|
bin | 11101110110101101011101… |
… | …111000001000110110001011 |
3 | 122012220110001020101222012021 |
4 | 131312231131320020312023 |
5 | 114202232041133002103 |
6 | 1143131435203025311 |
7 | 36441221146532656 |
oct | 3566553570106613 |
9 | 565813036358167 |
10 | 131303020203403 |
11 | 38923330929994 |
12 | 128874a396b237 |
13 | 5835a8b2b8a19 |
14 | 245d1588cc89d |
15 | 102a75d703bbd |
hex | 776b5de08d8b |
131303020203403 has 2 divisors, whose sum is σ = 131303020203404. Its totient is φ = 131303020203402.
The previous prime is 131303020203217. The next prime is 131303020203427. The reversal of 131303020203403 is 304302020303131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131303020203403 is a prime.
It is a super-2 number, since 2×1313030202034032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131303020203463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65651510101701 + 65651510101702.
It is an arithmetic number, because the mean of its divisors is an integer number (65651510101702).
Almost surely, 2131303020203403 is an apocalyptic number.
131303020203403 is a deficient number, since it is larger than the sum of its proper divisors (1).
131303020203403 is an equidigital number, since it uses as much as digits as its factorization.
131303020203403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 131303020203403 its reverse (304302020303131), we get a palindrome (435605040506534).
The spelling of 131303020203403 in words is "one hundred thirty-one trillion, three hundred three billion, twenty million, two hundred three thousand, four hundred three".
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