Base | Representation |
---|---|
bin | 1011111100010010001101… |
… | …1110011101110001010001 |
3 | 1201111020121220011012201011 |
4 | 2333010203132131301101 |
5 | 3210111333403301224 |
6 | 43531551540410521 |
7 | 2523430220212045 |
oct | 277044336356121 |
9 | 51436556135634 |
10 | 13130310212689 |
11 | 420259589924a |
12 | 15808aa3a6a41 |
13 | 74324bbc5347 |
14 | 3357207a2025 |
15 | 17b839875394 |
hex | bf12379dc51 |
13130310212689 has 2 divisors, whose sum is σ = 13130310212690. Its totient is φ = 13130310212688.
The previous prime is 13130310212597. The next prime is 13130310212699. The reversal of 13130310212689 is 98621201303131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11349433307664 + 1780876905025 = 3368892^2 + 1334495^2 .
It is a cyclic number.
It is not a de Polignac number, because 13130310212689 - 29 = 13130310212177 is a prime.
It is a super-2 number, since 2×131303102126892 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13130310212699) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565155106344 + 6565155106345.
It is an arithmetic number, because the mean of its divisors is an integer number (6565155106345).
Almost surely, 213130310212689 is an apocalyptic number.
It is an amenable number.
13130310212689 is a deficient number, since it is larger than the sum of its proper divisors (1).
13130310212689 is an equidigital number, since it uses as much as digits as its factorization.
13130310212689 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46656, while the sum is 40.
The spelling of 13130310212689 in words is "thirteen trillion, one hundred thirty billion, three hundred ten million, two hundred twelve thousand, six hundred eighty-nine".
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