Search a number
-
+
13130310212689 is a prime number
BaseRepresentation
bin1011111100010010001101…
…1110011101110001010001
31201111020121220011012201011
42333010203132131301101
53210111333403301224
643531551540410521
72523430220212045
oct277044336356121
951436556135634
1013130310212689
11420259589924a
1215808aa3a6a41
1374324bbc5347
143357207a2025
1517b839875394
hexbf12379dc51

13130310212689 has 2 divisors, whose sum is σ = 13130310212690. Its totient is φ = 13130310212688.

The previous prime is 13130310212597. The next prime is 13130310212699. The reversal of 13130310212689 is 98621201303131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11349433307664 + 1780876905025 = 3368892^2 + 1334495^2 .

It is a cyclic number.

It is not a de Polignac number, because 13130310212689 - 29 = 13130310212177 is a prime.

It is a super-2 number, since 2×131303102126892 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13130310212699) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565155106344 + 6565155106345.

It is an arithmetic number, because the mean of its divisors is an integer number (6565155106345).

Almost surely, 213130310212689 is an apocalyptic number.

It is an amenable number.

13130310212689 is a deficient number, since it is larger than the sum of its proper divisors (1).

13130310212689 is an equidigital number, since it uses as much as digits as its factorization.

13130310212689 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656, while the sum is 40.

The spelling of 13130310212689 in words is "thirteen trillion, one hundred thirty billion, three hundred ten million, two hundred twelve thousand, six hundred eighty-nine".