Base | Representation |
---|---|
bin | 1011111100010010010000… |
… | …0100010011111110100001 |
3 | 1201111020122120211021020221 |
4 | 2333010210010103332201 |
5 | 3210111343423242144 |
6 | 43531552533203041 |
7 | 2523430400433226 |
oct | 277044404237641 |
9 | 51436576737227 |
10 | 13130320134049 |
11 | 42025a0455318 |
12 | 15808b1790481 |
13 | 743250c8a181 |
14 | 335721c2594d |
15 | 17b83a684d84 |
hex | bf124113fa1 |
13130320134049 has 2 divisors, whose sum is σ = 13130320134050. Its totient is φ = 13130320134048.
The previous prime is 13130320134037. The next prime is 13130320134101. The reversal of 13130320134049 is 94043102303131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11812749033024 + 1317571101025 = 3436968^2 + 1147855^2 .
It is a cyclic number.
It is not a de Polignac number, because 13130320134049 - 25 = 13130320134017 is a prime.
It is a super-2 number, since 2×131303201340492 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13130320134749) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565160067024 + 6565160067025.
It is an arithmetic number, because the mean of its divisors is an integer number (6565160067025).
Almost surely, 213130320134049 is an apocalyptic number.
It is an amenable number.
13130320134049 is a deficient number, since it is larger than the sum of its proper divisors (1).
13130320134049 is an equidigital number, since it uses as much as digits as its factorization.
13130320134049 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23328, while the sum is 34.
The spelling of 13130320134049 in words is "thirteen trillion, one hundred thirty billion, three hundred twenty million, one hundred thirty-four thousand, forty-nine".
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