1313032120033 has 4 divisors (see below), whose sum is σ = 1313372023488. Its totient is φ = 1312692216580.

The previous prime is 1313032120003. The next prime is 1313032120039. The reversal of 1313032120033 is 3300212303131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1313032120033 - 2²⁵ = 1312998565601 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1313032119986 and 1313032120013.

It is not an unprimeable number, because it can be changed into a prime (1313032120039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 169945933 + ... + 169953658.

It is an arithmetic number, because the mean of its divisors is an integer number (328343005872).

Almost surely, 2^{1313032120033} is an apocalyptic number.

It is an amenable number.

1313032120033 is a deficient number, since it is larger than the sum of its proper divisors (339903455).

1313032120033 is an equidigital number, since it uses as much as digits as its factorization.

1313032120033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 339903454.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 1313032120033 its reverse (3300212303131), we get a palindrome (4613244423164).

The spelling of 1313032120033 in words is "one trillion, three hundred thirteen billion, thirty-two million, one hundred twenty thousand, thirty-three".