1313033111233 has 4 divisors (see below), whose sum is σ = 1313147868208. Its totient is φ = 1312918354260.

The previous prime is 1313033111213. The next prime is 1313033111239. The reversal of 1313033111233 is 3321113303131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1313033111233 - 2⁹ = 1313033110721 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1313033111198 and 1313033111207.

It is not an unprimeable number, because it can be changed into a prime (1313033111239) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57361323 + ... + 57384208.

It is an arithmetic number, because the mean of its divisors is an integer number (328286967052).

Almost surely, 2^{1313033111233} is an apocalyptic number.

It is an amenable number.

1313033111233 is a deficient number, since it is larger than the sum of its proper divisors (114756975).

1313033111233 is a wasteful number, since it uses less digits than its factorization.

1313033111233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 114756974.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 1313033111233 its reverse (3321113303131), we get a palindrome (4634146414364).

The spelling of 1313033111233 in words is "one trillion, three hundred thirteen billion, thirty-three million, one hundred eleven thousand, two hundred thirty-three".