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131304062219489 is a prime number
BaseRepresentation
bin11101110110101110011011…
…111111000111010011100001
3122012220112201212010212112122
4131312232123333013103201
5114202241204412010424
61143132130425034025
736441256031526515
oct3566563377072341
9565815655125478
10131304062219489
1138923816040005
1212887734925915
135835bc61472a3
14245d217056145
15102a7bee3445e
hex776b9bfc74e1

131304062219489 has 2 divisors, whose sum is σ = 131304062219490. Its totient is φ = 131304062219488.

The previous prime is 131304062219461. The next prime is 131304062219509. The reversal of 131304062219489 is 984912260403131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129249999979489 + 2054062240000 = 11368817^2 + 1433200^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131304062219489 is a prime.

It is a super-2 number, since 2×1313040622194892 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131304062219489.

It is not a weakly prime, because it can be changed into another prime (131304062219389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65652031109744 + 65652031109745.

It is an arithmetic number, because the mean of its divisors is an integer number (65652031109745).

Almost surely, 2131304062219489 is an apocalyptic number.

It is an amenable number.

131304062219489 is a deficient number, since it is larger than the sum of its proper divisors (1).

131304062219489 is an equidigital number, since it uses as much as digits as its factorization.

131304062219489 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2239488, while the sum is 53.

The spelling of 131304062219489 in words is "one hundred thirty-one trillion, three hundred four billion, sixty-two million, two hundred nineteen thousand, four hundred eighty-nine".