Base | Representation |
---|---|
bin | 1011111100010010101011… |
… | …0111111100100101110001 |
3 | 1201111020221112201011211020 |
4 | 2333010222313330211301 |
5 | 3210112112142124131 |
6 | 43532012133010053 |
7 | 2523433255214004 |
oct | 277045267744561 |
9 | 51436845634736 |
10 | 13130434333041 |
11 | 4202649964753 |
12 | 1580923a83929 |
13 | 74326b83283c |
14 | 33573307153b |
15 | 17b8456e1996 |
hex | bf12adfc971 |
13130434333041 has 8 divisors (see below), whose sum is σ = 17507413916160. Its totient is φ = 8753538819312.
The previous prime is 13130434333021. The next prime is 13130434333099. The reversal of 13130434333041 is 14033343403131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13130434333041 - 243 = 4334341310833 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13130434332993 and 13130434333011.
It is not an unprimeable number, because it can be changed into a prime (13130434333021) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20652006 + ... + 21278303.
It is an arithmetic number, because the mean of its divisors is an integer number (2188426739520).
Almost surely, 213130434333041 is an apocalyptic number.
It is an amenable number.
13130434333041 is a deficient number, since it is larger than the sum of its proper divisors (4376979583119).
13130434333041 is a wasteful number, since it uses less digits than its factorization.
13130434333041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42034695.
The product of its (nonzero) digits is 46656, while the sum is 33.
Adding to 13130434333041 its reverse (14033343403131), we get a palindrome (27163777736172).
The spelling of 13130434333041 in words is "thirteen trillion, one hundred thirty billion, four hundred thirty-four million, three hundred thirty-three thousand, forty-one".
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