1313043441131 has 4 divisors (see below), whose sum is σ = 1358320801200. Its totient is φ = 1267766081064.

The previous prime is 1313043441071. The next prime is 1313043441133. The reversal of 1313043441131 is 1311443403131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1313043441131 is a prime.

It is a super-2 number, since 2×1313043441131² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (29), and also a Moran number because the ratio is a prime number: 45277360039 = 1313043441131 / (1 + 3 + 1 + 3 + 0 + 4 + 3 + 4 + 4 + 1 + 1 + 3 + 1).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1313043441094 and 1313043441103.

It is not an unprimeable number, because it can be changed into a prime (1313043441133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22638679991 + ... + 22638680048.

It is an arithmetic number, because the mean of its divisors is an integer number (339580200300).

Almost surely, 2^{1313043441131} is an apocalyptic number.

1313043441131 is a deficient number, since it is larger than the sum of its proper divisors (45277360069).

1313043441131 is an equidigital number, since it uses as much as digits as its factorization.

1313043441131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45277360068.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 1313043441131 its reverse (1311443403131), we get a palindrome (2624486844262).

The spelling of 1313043441131 in words is "one trillion, three hundred thirteen billion, forty-three million, four hundred forty-one thousand, one hundred thirty-one".