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131305511041 = 1097931195937
BaseRepresentation
bin111101001001001101…
…0110001100010000001
3110112220220111002002121
41322102122301202001
54122403202323131
6140153152444241
712325605266665
oct1722232614201
9415826432077
10131305511041
11507605a0981
1221545b49681
13c4c74bc083
1464d8a228a5
153637791911
hex1e926b1881

131305511041 has 4 divisors (see below), whose sum is σ = 131306816772. Its totient is φ = 131304205312.

The previous prime is 131305511017. The next prime is 131305511101. The reversal of 131305511041 is 140115503131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 55922317441 + 75383193600 = 236479^2 + 274560^2 .

It is a cyclic number.

It is not a de Polignac number, because 131305511041 - 211 = 131305508993 is a prime.

It is a super-2 number, since 2×1313055110412 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131305510997 and 131305511015.

It is not an unprimeable number, because it can be changed into a prime (131305511741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 488176 + ... + 707761.

It is an arithmetic number, because the mean of its divisors is an integer number (32826704193).

Almost surely, 2131305511041 is an apocalyptic number.

It is an amenable number.

131305511041 is a deficient number, since it is larger than the sum of its proper divisors (1305731).

131305511041 is a wasteful number, since it uses less digits than its factorization.

131305511041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1305730.

The product of its (nonzero) digits is 900, while the sum is 25.

The spelling of 131305511041 in words is "one hundred thirty-one billion, three hundred five million, five hundred eleven thousand, forty-one".

Divisors: 1 109793 1195937 131305511041