131310001113 has 32 divisors (see below), whose sum is σ = 182029034880. Its totient is φ = 84130099200.

The previous prime is 131310001111. The next prime is 131310001153. The reversal of 131310001113 is 311100013131.

It is not a de Polignac number, because 131310001113 - 2¹ = 131310001111 is a prime.

It is a super-2 number, since 2×131310001113² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131310001092 and 131310001101.

It is not an unprimeable number, because it can be changed into a prime (131310001111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3017913 + ... + 3061113.

It is an arithmetic number, because the mean of its divisors is an integer number (5688407340).

Almost surely, 2^131310001113 is an apocalyptic number.

It is an amenable number.

131310001113 is a deficient number, since it is larger than the sum of its proper divisors (50719033767).

131310001113 is a wasteful number, since it uses less digits than its factorization.

131310001113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43577.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 131310001113 its reverse (311100013131), we get a palindrome (442410014244).

The spelling of 131310001113 in words is "one hundred thirty-one billion, three hundred ten million, one thousand, one hundred thirteen".